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R2.1.5 Atom economy
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- this is msj CM in this video I'll be looking at atom economy here we have the equation for calculating percentage atom economy that appears in the IB data
- booklet so that's percentage atom economy equals the molar mass of the desired product divided by the molar mass of all reactants multiplied by
- 100 there are other versions of the equation and they are atom economy equals mass of desired product divided by mass of all reactants multiplied by
- 100 and mass of desired product divided by mass of all products multiplied by 100 to calculate the atom economy for a reaction either one of these equations
- can be used in this video I'll be using the top equation because this one appears in the IB data booklet next we look at an example ion
- is produced by the reduction of ion oxide in a blast furnace Cal the atom economy of the reaction here we have the balanced
- chemical equation for the reaction ion oxide reacts with carbon monoxide to form ion and carbon dioxide we'll start by finding the total
- of all the molar masses of the atoms in the reactants so we have two atoms of ion so that's 2 multiplied by the molar mass of ion which is 55.8 5 we have six
- atoms of oxygen so that's 6 multiplied by the mol mass of oxygen oygen which is 16. and we have three carbon atoms so that's 3 multiplied by the mol mass of
- carbon which is 12.01 when we add these together we get a total of 243.166
- us 11.7 next we'll use the equation to calculate the percentage atom economy
- the total of the molar masses of our desired product which was ion is 11.7 the total of the molar masses of the reactants was
- 243.166 which I rounded to two significant figures this percentage atom economy
- tells us that 54% by mass of the reactants do not end up in the desired product in other words they are wasted the higher the atom economy for a
- chemical reaction the less waste is produced and the more efficient the reaction is
Zum Nachlesen
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